Cara Mengirim file pada form menggunakan Jquery Ajax

Berikut contoh baris kode mengirim file menggunakan ajax:

1. Kode HTML


<!DOCTYPE html>
<html>
<body>

<h1>jQuery Ajax submit Multipart form</h1>

<form method="POST" enctype="multipart/form-data" id="fileUploadForm">
    <input type="text" name="extraField"/><br/><br/>
    <input type="file" name="files"/><br/><br/>
    <input type="file" name="files"/><br/><br/>
    <input type="submit" value="Submit" id="btnSubmit"/>
</form>

<h1>Ajax Post Result</h1>
<span id="result"></span>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>

</body>
</html>
2. Kode Jquery Ajax



$(document).ready(function () {

    $("#btnSubmit").click(function (event) {

        //stop submit the form, we will post it manually.
        event.preventDefault();

        // Get form
        var form = $('#fileUploadForm')[0];

  // Create an FormData object 
        var data = new FormData(form);

  // If you want to add an extra field for the FormData
        data.append("CustomField", "This is some extra data, testing");

  // disabled the submit button
        $("#btnSubmit").prop("disabled", true);

        $.ajax({
            type: "POST",
            enctype: 'multipart/form-data',
            url: "/api/upload/multi",
            data: data,
            processData: false,
            contentType: false,
            cache: false,
            timeout: 600000,
            success: function (data) {

                $("#result").text(data);
                console.log("SUCCESS : ", data);
                $("#btnSubmit").prop("disabled", false);

            },
            error: function (e) {

                $("#result").text(e.responseText);
                console.log("ERROR : ", e);
                $("#btnSubmit").prop("disabled", false);

            }
        });

    });

});
 
 

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